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넘겨온 변수의 이름을 추출하는 함수..

· 16년 전 · 1366 · 1

값이아니라 변수명입니다~

 Here s a function to get the name of a given variable.  Explanation and examples below.

   function vname(&$var, $scope=false, $prefix='unique', $suffix='value')
   {
     if($scope) $vals = $scope;
     else      $vals = $GLOBALS;
     $old = $var;
     $var = $new = $prefix.rand().$suffix;
     $vname = FALSE;
     foreach($vals as $key => $val) {
       if($val === $new) $vname = $key;
     }
     $var = $old;
     return $vname;
   }


 Explanation:

 The problem with figuring out what value is what key in that variables scope is that several variables might have the same value.  To remedy this, the variable is passed by reference and its value is then modified to a random value to make sure there will be a unique match.  Then we loop through the scope the variable is contained in and when there is a match of our modified value, we can grab the correct key.

 Examples:

 1.  Use of a variable contained in the global scope (default):
 < ?php
   $my_global_variable = "My global string.";
   echo vname($my_global_variable); // Outputs:  my_global_variable
 ? >

 2.  Use of a local variable:
 < ?php
   function my_local_func()
   {
     $my_local_variable = "My local string.";
     return vname($my_local_variable, get_defined_vars());
   }
   echo my_local_func(); // Outputs: my_local_variable
 ? >

 3.  Use of an object property:
 < ?php
   class myclass
   {
     public function __constructor()
     {
       $this->my_object_property = "My object property  string.";
     }
   }
   $obj = new myclass;
   echo vname($obj->my_object_property, $obj); // Outputs: my_object_property
 ? >
 =>2줄로
 < ?php
 function var_name(&$var, $scope=0)
 {
     $old = $var;
     if (($key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && $var = $old) return $key;
 }
 ? >

[이 게시물은 관리자님에 의해 2011-10-31 17:16:08 PHP & HTML에서 이동 됨]

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찾다찾다 여기서 찾게 되었네요. 정말 감사합니다.
그러고보니 딱 일년전 글이군요 ㅎ

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