메뉴 코드 수정 채택완료

</p>

<p><!-- 좌측네비 시작 { --></p>

<p><script type="text/javascript">

<!--

    function display_submenu(num) {

         document.getElementById("mysub"+num).style.display="block";

    }

//-->

</script></p>

<p><style TYPE="text/css">

<!--

#mysubmenu ul {list-style:none; font-size:10pt; margin:0 0 10px 0; padding:0;}

#mysubmenu .leftmenu_b {line-height:50px; background-color:#34495E;text-align:center;font-size:11pt;font-weight:bold; color:#fff}

#mysubmenu .leftmenu_s {line-height:35px; padding-left:15px; background-color:#fff;border-left:1px solid #ccc;border-right:1px solid #ccc;border-bottom:1px solid #ccc;}

#mysubmenu a {text-decoration:none;}

#mysubmenu a:hover {color:blue;}

//-->

</style></p>

<p><div id="mysubmenu">

    <?php

    $sql = " select *

                from {$g5['menu_table']}

                where me_use = '1'

                  and length(me_code) = '2'

                order by me_order, me_id ";

    $result = sql_query($sql, false);

    $gnb_zindex = 999; // gnb_1dli z-index 값 설정용</p>

<p>    for ($i=0; $row=sql_fetch_array($result); $i++) {

    ?>

    <ul id="mysub<?php echo $i ?>" style="display:none;">

        <a href="<?php echo $row['me_link']; ?>" target="_<?php echo $row['me_target']; ?>" ><li class="leftmenu_b"><?php echo $row['me_name'] ?></li></a>

            <?php

            $sql2 = " select *

                        from {$g5['menu_table']}

                        where me_use = '1'

                          and length(me_code) = '4'

                          and substring(me_code, 1, 2) = '{$row['me_code']}'

                        order by me_order, me_id ";

            $result2 = sql_query($sql2);

            

            //좌측 서브메뉴 전체 리스트에서 현재 페이지에 해당하는 대메뉴 리스트만 보여줌

            if ( ($row['me_name']==$board['bo_subject'])||($row['me_name']==$g5['title']) ) {

                echo ("<script language='javascript'> display_submenu(" .$i. " ); </script> ");

            } else {</p>

<p>            }

    

            for ($k=0; $row2=sql_fetch_array($result2); $k++) {

                if($k == 0)

                    echo '<ul>'.PHP_EOL;

            ?>

                <a href="<?php echo $row2['me_link']; ?>" target="_<?php echo $row2['me_target']; ?>" ><li class="leftmenu_s"><?php echo $row2['me_name'] ?></li></a>

            <?php  </p>

<p>                //좌측 서브메뉴 전체 리스트에서 현재 페이지에 해당하는 대메뉴 리스트만 보여줌

                if ( ($row2['me_name']==$board['bo_subject'])||($row2['me_name']==$g5['title']) ) {

                    echo ("<script language='javascript'> display_submenu(" .$i. " ); </script> ");

                } else {</p>

<p>                }</p>

<p>            }</p>

<p>            if($k > 0)

                echo '</ul>'.PHP_EOL;

            ?>

    </ul>

    <?php } ?></p>

<p>

</div></p>

<p> </p>

<p><!-- }좌측네비 끝 --></p>

<p>