테스트 사이트 - 개발 중인 베타 버전입니다

php와 자바스크립트 연동

· 19년 전 · 2170
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME="Generator" CONTENT="EditPlus 1.2">
<META NAME="Author" CONTENT="">
<META NAME="Keywords" CONTENT="">
<META NAME="Description" CONTENT="">
</HEAD>

<BODY BGCOLOR="#FFFFFF">


<script language="javascript">


function hrewarp(menu) {
var myindex = doc.options[doc.selectedIndex].value;
location.href=myindex;
}

function OpenNoticeWin(url) {
window.open(url,"notice_win",'toolbar=no,location=no,directory=no,status=no,menubar=no,scrollbars=yes,resizable=yes,copyhistory=no,width=510,height=400');
}


function member_select(){

var doc = document.teamlist.team_nm;
var Member = document.teamlist.member_nm;


<?php

//--------------------------------------------------------------------------------
// MySQL DB 접속
//--------------------------------------------------------------------------------

$connect=mysql_connect( "", "mysql", "") or die( "SQL server에 연결할 수 없습니다.");
mysql_select_db("test",$connect);


//--------------------------------------------------------------------------------
// 제일 큰 팀의 인원수를 알아낸다.
//--------------------------------------------------------------------------------

$que1="select team_nm ,count(*)
from team group by team_nm
order by 2 Desc
limit 1
" ;

$result1 = mysql_query($que1,$connect ) ;

$row1 = mysql_fetch_array($result1) ;

$member_max = $row1[1] ;

// echo $member_max : 제일 큰 팀의 인원수





//--------------------------------------------------------------------------------
// 팀이름의 목록를 알아낸다
//--------------------------------------------------------------------------------

$que2="select distinct team_nm from team " ;
$result2 = mysql_query($que2,$connect );
$team_max = mysql_num_rows($result2) ;

// echo $team_max : 팀의 수



//========== 팀이름을 루프로 돌린다.: [팀의 수만큼] =======

$row_team = mysql_fetch_array($result2);

while($row_team)
{

echo(" if (document.teamlist.team_nm.options[document.teamlist.team_nm.selectedIndex].value == '$row_team[0]') ");
echo(" {

");
//--------------------------------
// $row_team[0] 에 속하는 팀원의 목록
//---------------------------------

$que3="select member_nm from team where team_nm='$row_team[0]'" ;
$result3 = mysql_query($que3,$connect );
//======== 팀원을 작은 루프로 돌린다 [제일 큰 팀의 인원수 만큼]======
for($i=0 ; $i < $member_max ; $i++)
{
$row_member = mysql_fetch_array($result3);

//if($row_member[0])
@print("
document.teamlist.member_nm.options[$i].text = '$row_member[0]' ;
document.teamlist.member_nm.options[$i].value= '$row_member[0]' ; ");

}
//======== 작은 루프 끝 ============================================
echo(" } ");

$row_team = mysql_fetch_array($result2);

}
// ========== 큰루프 끝===========





?>
document.teamlist.member_nm.selectedIndex = 0 ;
}


</SCRIPT>

<form method="post" name=teamlist>

팀선택 <select name="team_nm" onchange="member_select()">


<?php
//====== 팀이름 목록=========

$que2="select distinct team_nm from team " ;
$result2 = mysql_query($que2,$connect );
$row_team = mysql_fetch_array($result2);


echo("<option value=''>팀선택</option>");

while($row_team)
{

echo("<option value='$row_team[0]'>$row_team[0]</option>");
$row_team = mysql_fetch_array($result2);

}


?>

</select>

팀원선택<select name="member_nm">

<?php
for($i=0 ; $i < $member_max ; $i++ )
{

echo("<option value=''></option>");

}

?>
</font>
</select>

</form>


</BODY>
</HTML><div class='small'>[이 게시물은 관리자님에 의해 2011-10-31 17:16:08 PHP & HTML에서 이동 됨]</div>

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