테스트 사이트 - 개발 중인 베타 버전입니다

고수님 봐주세요~

· 13년 전 · 728 · 1
제가 이벤트 페이지를 만드는데 처음에는 아이디하나만 나오게하는게 막혀서 찾아보니 group by로하면
한아이디만 나온다는걸 알게됐는데
두번째 문제가 응모횟수를 뽑는건 어떻게 해야하는거죠?
그냥 cnt하면 전체 응모횟수가 나오고
위에서 user_id=$user_id해봤자 user_id를 못받으니 소용없는거구..
어떻하면 응모횟수를 뽑을수있을가요?
고수님들 도와주세요

<table border="0" cellspacing="1" cellpadding="0" width="1300" bgcolor="#383838">
<tr height="30">
<td align="center" style="width:35px; background:#EFEFEF;">번호</td>
<td align="center" style="width:80px; background:#EFEFEF;">아이디</td>
<td align="center"style="width:55px; background:#EFEFEF;">이름</td>
<td align="center" style="width:90px; background:#EFEFEF;">연락처</td>
<td align="center" style="width:80px; background:#EFEFEF;">응모횟수</td>
<td align="center" style="width:40px; background:#EFEFEF;">삭제</td>
</tr>
<?
$Qry = "SELECT count(*) as cnt FROM 응모테이블 teb JOIN 회원테이블 tc ON teb.user_id = tc.id WHERE teb.del_flag = 'N' AND teb.user_id !=''";
$DB->query($Qry);
$DB->next_record();
$total_count = $DB->FieldByName["CNT"];
$DB->free_result();
$total_page_cnt = (ceil($total_count / $page_size) <= 0) ? 1 : ceil($total_count / $page_size);
if ($page > $total_page_cnt) {
$page = $total_page_cnt;
}
$Qry = "
SELECT
teb.seq AS seq, teb.user_id AS user_id,
teb.subject AS subject ,
teb.contents AS contents ,
tc.name AS name, tc.resident AS resident,
tc.addr2 AS addr2, tc.phone AS phone,
tc.hphone AS hphone
FROM
응모테이블 teb JOIN 회원테이블 tc
ON
teb.user_id = tc.id
WHERE
teb.delYN = 'N' AND teb.event_seq = 66 AND teb.user_id!=''
group by teb.user_id
order by teb.seq desc";

$DB->query($Qry);
$i = 0;
while ($DB->next_record()) {
$desccnt = $total_count - $i - ($page_size * ($page -1));
?>
<tr height=30>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF">???????번 </td>
<td align="center" bgcolor="#FFFFFF">삭제</td>
</tr>
<?$i++;}?>
</table>

댓글 작성

댓글을 작성하시려면 로그인이 필요합니다.

로그인하기

댓글 1개

$Qry = "SELECT a.user_id, count(b.id) as cnt, b.id FROM member as a left join board as b on a.user_id = b.id WHERE a.del_flag = 'N' 이러케 하면 나올꺼 같은데요....

게시글 목록

번호 제목
28080
7612
7598
7595
19842
28079
19840
7593
28076
7590
28072
28065
19836
7586
28058
7573
31754
7552
28057
30993
28052
7546
7544
7538
7519
30992
19834
7517
7512
7511
19832
19820
7509
24658
7508
7507
19818
30990
7506
7505
7498
7492
28051
7481
30988
19813
19812
7477
7476
7471
7467
19810
7464
19809
7463
7457
30980
7450
28043
7447
7440
28040
7438
7430
7427
7423
7414
7408
7405
7401
7400
19808
7398
7393
7389
19805
7382
7379
7378
7363
7361
7356
19804
7355
7352
19786
7342
7336
7332
19783
7328
7325
7324
28036
19782
7321
26574
7314
7312
19781