애왜안될까요;;;

<?
 include "dbcon.php";
 if($num == "")
 {popup_back("잘못된 경로 입니다.");}

 
 $sql = "select * from message wgere num = $num";
 $res = mysql_query($sql);

 show();

 mysql_close($con);
//--------------show()함수--------------//
function show()
{
 global $res;

 $num = mysql_result($res, 0, 'num');
 $name = mysql_result($res, 0, 'name');
 $email = mysql_result($res, 0, 'email');
 $message = mysql_result($res, 0, 'message');
 $writedate = mysql_result($res, 0, 'writedate');
 $sourceip = mysql_result($res, 0, 'sourceip');

 echo("
 <table border=1>
  <tr>
   <td>번호</td>
   <td>이름</td>
   <td>이메일</td>
   <td>작성일</td>
   <td>IP</td>
  </tr>
  <tr>
   <td colspan=5>메시지</td>
  </tr>
  </table>
 ");
}
//--------------show()함수--------------//
?>

 

 

이렇게 했거든여

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 18

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 19

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 20

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 21

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 22

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 23
이런 에러가나네요

 

mysql연결은 다되있고 확인까지 했는데 저러네용;;