테스트 사이트 - 개발 중인 베타 버전입니다

고수님 봐주세요~

· 13년 전 · 721 · 1
제가 이벤트 페이지를 만드는데 처음에는 아이디하나만 나오게하는게 막혀서 찾아보니 group by로하면
한아이디만 나온다는걸 알게됐는데
두번째 문제가 응모횟수를 뽑는건 어떻게 해야하는거죠?
그냥 cnt하면 전체 응모횟수가 나오고
위에서 user_id=$user_id해봤자 user_id를 못받으니 소용없는거구..
어떻하면 응모횟수를 뽑을수있을가요?
고수님들 도와주세요

<table border="0" cellspacing="1" cellpadding="0" width="1300" bgcolor="#383838">
<tr height="30">
<td align="center" style="width:35px; background:#EFEFEF;">번호</td>
<td align="center" style="width:80px; background:#EFEFEF;">아이디</td>
<td align="center"style="width:55px; background:#EFEFEF;">이름</td>
<td align="center" style="width:90px; background:#EFEFEF;">연락처</td>
<td align="center" style="width:80px; background:#EFEFEF;">응모횟수</td>
<td align="center" style="width:40px; background:#EFEFEF;">삭제</td>
</tr>
<?
$Qry = "SELECT count(*) as cnt FROM 응모테이블 teb JOIN 회원테이블 tc ON teb.user_id = tc.id WHERE teb.del_flag = 'N' AND teb.user_id !=''";
$DB->query($Qry);
$DB->next_record();
$total_count = $DB->FieldByName["CNT"];
$DB->free_result();
$total_page_cnt = (ceil($total_count / $page_size) <= 0) ? 1 : ceil($total_count / $page_size);
if ($page > $total_page_cnt) {
$page = $total_page_cnt;
}
$Qry = "
SELECT
teb.seq AS seq, teb.user_id AS user_id,
teb.subject AS subject ,
teb.contents AS contents ,
tc.name AS name, tc.resident AS resident,
tc.addr2 AS addr2, tc.phone AS phone,
tc.hphone AS hphone
FROM
응모테이블 teb JOIN 회원테이블 tc
ON
teb.user_id = tc.id
WHERE
teb.delYN = 'N' AND teb.event_seq = 66 AND teb.user_id!=''
group by teb.user_id
order by teb.seq desc";

$DB->query($Qry);
$i = 0;
while ($DB->next_record()) {
$desccnt = $total_count - $i - ($page_size * ($page -1));
?>
<tr height=30>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="center" bgcolor="#FFFFFF">???????번 </td>
<td align="center" bgcolor="#FFFFFF">삭제</td>
</tr>
<?$i++;}?>
</table>

댓글 작성

댓글을 작성하시려면 로그인이 필요합니다.

로그인하기

댓글 1개

13년 전
$Qry = "SELECT a.user_id, count(b.id) as cnt, b.id FROM member as a left join board as b on a.user_id = b.id WHERE a.del_flag = 'N' 이러케 하면 나올꺼 같은데요....

게시글 목록

번호 제목
12463
12462
12461
12460
12459
12458
12457
12456
12455
12454
12453
12452
12451
12450
12449
12448
12447
12446
12445
12444
12443
12442
12441
12440
12439