서브메뉴(2차메뉴) 리스트 뽑는 기능에서 현재페이지명 강조는 어떻게 해야할까요? 채택완료

</p>

<p> <a href="<?php echo $row2['me_link']; ?>" target="_<?php echo $row2['me_target']; ?>">

             <li class="leftmenu_s"><?php echo $row2['me_name'] ?></li>

           </a></p>

<p>

</p>

<p><script type="text/javascript"></p>

<p>    function display_submenu(num) {

         document.getElementById("mysub"+num).style.display="block";

    }</p>

<p>    function display_submenu(num) {

         document.getElementById("mysub"+num).style.display="block";

    }</p>

<p>

</script></p>

<p><style TYPE="text/css">

#submenu_list {font-size: 0; width:800px; margin:0 auto}

#mysubmenu{margin:5px auto}

#mysubmenu ul {list-style:none; font-size:11pt; margin:0; padding:0; text-align: center}

#mysubmenu .leftmenu_b {margin-bottom:15px; background-color:#E7EDF1;border:1px solid gray;text-align:center;font-size:12px;font-weight:bold;display: none}

#mysubmenu .leftmenu_s {line-height: 24px; margin-bottom:5px; width:18%; text-align: center; display: inline-block; margin:5px auto; font-size: 13px; color:#5e5e5e; background: #eee; padding:5px}

#mysubmenu .leftmenu_s:hover, :focus {background: #ddd}

#mysubmenu a {text-decoration:none; color:#999; }

#mysubmenu a:hover {color:black;}

@media only screen and (min-width : 721px) and (max-width : 1199px)  {

  #submenu_list {font-size: 0; width:95%; margin:0 auto}</p>

<p>}</p>

<p>@media only screen and (min-width : 320px) and (max-width : 720px) {

  #submenu_list {font-size: 0; width:95%; margin:0 auto}

  #mysubmenu .leftmenu_s {line-height: 24px;width:45%; text-align: center; display: inline-block; margin:1px auto; font-size: 12px; color:#5e5e5e; background: #eee; padding:5px}

}

</style></p>

<p><div id="mysubmenu">

    <?php

    $sql = " select *

                from {$g5['menu_table']}

                where me_use = '1'

                  and length(me_code) = '2'

                order by me_order, me_id ";

    $result = sql_query($sql, false);

    $gnb_zindex = 999; // gnb_1dli z-index 값 설정용</p>

<p>    for ($i=0; $row=sql_fetch_array($result); $i++) {

    ?>

    <ul id="mysub<?php echo $i ?>" style="display:none;">

        <a href="<?php echo $row['me_link']; ?>" target="_<?php echo $row['me_target']; ?>" ><li class="leftmenu_b"><?php echo $row['me_name'] ?></li></a>

            <?php

            $sql2 = " select *

                        from {$g5['menu_table']}

                        where me_use = '1'

                          and length(me_code) = '4'

                          and substring(me_code, 1, 2) = '{$row['me_code']}'

                        order by me_order, me_id ";

            $result2 = sql_query($sql2);</p>

<p>            //좌측 서브메뉴 전체 리스트에서 현재 페이지에 해당하는 대메뉴 리스트만 보여줌

            if ( ($row['me_name']==$board['bo_subject'])||($row['me_name']==$g5['title']) ) {

                echo ("<script language='javascript'> display_submenu(" .$i. " ); </script> ");

            }</p>

<p>            for ($k=0; $row2=sql_fetch_array($result2); $k++) {

                if($k == 0)

                    echo '<ul>'.PHP_EOL;

            ?></p>

<p>           <a href="<?php echo $row2['me_link']; ?>" target="_<?php echo $row2['me_target']; ?>">

             <li class="leftmenu_s"><?php echo $row2['me_name'] ?></li>

           </a></p>

<p>            <?php</p>

<p>                //좌측 서브메뉴 전체 리스트에서 현재 페이지에 해당하는 대메뉴 리스트만 보여줌

                if ( ($row2['me_name']==$board['bo_subject'])||($row2['me_name']==$g5['title']) ) {

                    echo ("<script language='javascript'> display_submenu(" .$i. " ); </script> ");

                }</p>

<p>            }</p>

<p>            if($k > 0)

                echo '</ul>'.PHP_EOL;

            ?>

    </ul></p>

<p>    <?php } ?></p>

<p>

</div>

 </p>

<p>