다른 테이블 데이타 삽입하기 채택완료

// a10테이블에 자료업데이트</p><p>$sql = " update g4_write_a10 set wr_9 = '$wr_9', wr_10 = '$wr_10'  where wr_link2 = '$wr_link2' and ( DATE_FORMAT(wr_6, '%Y-%m-%d %H:%i:%s') >= '$today' and DATE_FORMAT(wr_6, '%Y-%m-%d %H:%i:%s') <= '{$nextday}')"; <span class="Apple-tab-span" style="font-size: 11pt; line-height: 1.5; white-space: pre;">	</span><span style="font-size: 11pt; line-height: 1.5;">  </span></p><p>sql_query($sql);  //여기까진 업데이트햇는데,....아래가...</p><p> </p><p>//a20테이블에 위자료업데이트</p><p>//위에 a10테이블 업데이트할때 group_id 와 같은 열에 업데이트 </p><p>$sql = " update <span style="font-size: 14.6667px;">g4_write_a20</span> set wr_9 = '$wr_9', wr_10 = '$wr_10'  where bo_table = 'a10' and <span style="font-family: sans-serif; font-size: 13.12px; font-weight: bold; line-height: normal; white-space: nowrap; background-color: rgb(229, 229, 229);">group_id</span> = '$<span style="font-family: sans-serif; font-size: 13.12px; font-weight: bold; line-height: normal; white-space: nowrap; background-color: rgb(229, 229, 229);">group_id</span>'  "; </p><p><span style="font-size: 14.6667px;">sql_query($sql);